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Physics (SSC, Railway, Police & All State exam)Chapter Unit

Physics: Periodic Motion

Introduction to Periodic Motion

  1. Definition:

    • Periodic motion is a type of motion that repeats itself at regular intervals of time.
    • Examples:
      • Motion of a pendulum.
      • Oscillations of a spring.
      • Revolution of the Earth around the Sun.
  2. Key Parameters:

    • Time Period (TTT):
      • The time taken for one complete cycle of motion.
      • SI Unit: Seconds (sss).
    • Frequency (fff):
      • The number of cycles completed in one second.
      • Relation to time period: f=1Tf = \frac{1}{T}f=T1​
      • SI Unit: Hertz (HzHzHz).
    • Angular Frequency (ω\omegaω):
      • The rate of change of angular displacement.
      • Relation to frequency: ω=2πf=2πT\omega = 2\pi f = \frac{2\pi}{T}ω=2πf=T2π​
      • SI Unit: Radians per second (rad/srad/srad/s).

Types of Periodic Motion

  1. Oscillatory Motion:

    • A type of periodic motion in which an object moves back and forth about a mean position.
    • Example: Simple pendulum.
  2. Rotational Motion:

    • A type of periodic motion in which an object rotates about a fixed axis.
    • Example: Spinning wheel.
  3. Simple Harmonic Motion (SHM):

    • A special type of oscillatory motion where the restoring force is directly proportional to displacement and acts in the opposite direction.
    • Equation of motion: F=−kxora=−ω2xF = -kx \quad \text{or} \quad a = -\omega^2 xF=−kxora=−ω2x

Simple Harmonic Motion (SHM)

  1. Characteristics:

    • The motion is sinusoidal in nature.
    • The restoring force FFF is proportional to displacement xxx.
  2. Equation of SHM:

    • Displacement as a function of time: x(t)=Acos⁡(ωt+ϕ)x(t) = A \cos(\omega t + \phi)x(t)=Acos(ωt+ϕ)
      • AAA: Amplitude.
      • ω\omegaω: Angular frequency.
      • ϕ\phiϕ: Phase constant.
  3. Velocity in SHM:

    • Velocity is the time derivative of displacement: v(t)=−Aωsin⁡(ωt+ϕ)v(t) = -A \omega \sin(\omega t + \phi)v(t)=−Aωsin(ωt+ϕ)
    • Maximum velocity: vmax=Aωv_{\text{max}} = A \omegavmax​=Aω
  4. Acceleration in SHM:

    • Acceleration is the time derivative of velocity: a(t)=−Aω2cos⁡(ωt+ϕ)a(t) = -A \omega^2 \cos(\omega t + \phi)a(t)=−Aω2cos(ωt+ϕ)
    • Maximum acceleration: amax=Aω2a_{\text{max}} = A \omega^2amax​=Aω2

Energy in SHM

  1. Kinetic Energy (KE):

    • Energy due to motion: KE=12mv2KE = \frac{1}{2} mv^2KE=21​mv2
      • Substituting vvv: KE=12mω2(A2−x2)KE = \frac{1}{2} m \omega^2 (A^2 - x^2)KE=21​mω2(A2−x2)
  2. Potential Energy (PE):

    • Energy due to position: PE=12kx2PE = \frac{1}{2} k x^2PE=21​kx2
  3. Total Energy (TE):

    • Sum of kinetic and potential energy: TE=12kA2TE = \frac{1}{2} k A^2TE=21​kA2
    • Remains constant throughout the motion.

Numerical Example

  1. Example 1: A body of mass 2 kg2 \, kg2kg is executing SHM with an amplitude of 0.1 m0.1 \, m0.1m and angular frequency 5 rad/s5 \, rad/s5rad/s. Find the total energy of the system.

    • Total Energy: TE=12mω2A2TE = \frac{1}{2} m \omega^2 A^2TE=21​mω2A2
    • Substituting values: TE=12⋅2⋅(5)2⋅(0.1)2TE = \frac{1}{2} \cdot 2 \cdot (5)^2 \cdot (0.1)^2TE=21​⋅2⋅(5)2⋅(0.1)2 TE=1⋅25⋅0.01=0.25 JTE = 1 \cdot 25 \cdot 0.01 = 0.25 \, JTE=1⋅25⋅0.01=0.25J
  2. Example 2: A particle in SHM has a maximum velocity of 3 m/s3 \, m/s3m/s and an angular frequency of 2 rad/s2 \, rad/s2rad/s. Find its amplitude.

    • Formula for maximum velocity: vmax=Aωv_{\text{max}} = A \omegavmax​=Aω
      • Solving for AAA: A=vmaxω=32=1.5 mA = \frac{v_{\text{max}}}{\omega} = \frac{3}{2} = 1.5 \, mA=ωvmax​​=23​=1.5m

Examples of Simple Harmonic Motion (SHM)

  1. Spring-Mass System:

    • A mass attached to a spring exhibits SHM when displaced from its equilibrium position.
    • Time Period: T=2πmkT = 2\pi \sqrt{\frac{m}{k}}T=2πkm​​
      • mmm: Mass of the object.
      • kkk: Spring constant.
    • Angular Frequency: ω=km\omega = \sqrt{\frac{k}{m}}ω=mk​​
  2. Simple Pendulum:

    • A pendulum consisting of a small bob of mass mmm suspended by a string of length LLL performs SHM for small angular displacements.
    • Time Period: T=2πLgT = 2\pi \sqrt{\frac{L}{g}}T=2πgL​​
      • LLL: Length of the pendulum.
      • ggg: Acceleration due to gravity.
    • Angular Frequency: ω=gL\omega = \sqrt{\frac{g}{L}}ω=Lg​​
  3. Oscillations of a Liquid in a U-Tube:

    • The liquid column oscillates when displaced from its equilibrium level.
    • Time Period: T=2πl2gT = 2\pi \sqrt{\frac{l}{2g}}T=2π2gl​​
      • lll: Length of the liquid column.

Damped Harmonic Motion

  1. Definition:

    • When the amplitude of oscillation decreases over time due to resistive forces (like friction or air resistance), the motion is called damped harmonic motion.
  2. Types of Damping:

    • Under-damped: Oscillations occur with gradually decreasing amplitude.
    • Critically Damped: The system returns to equilibrium without oscillating.
    • Over-damped: The system returns to equilibrium slower than the critically damped case.
  3. Equation of Motion: md2xdt2+bdxdt+kx=0m\frac{d^2x}{dt^2} + b\frac{dx}{dt} + kx = 0mdt2d2x​+bdtdx​+kx=0

    • bbb: Damping coefficient.

Forced Oscillations and Resonance

  1. Forced Oscillations:

    • When a periodic external force acts on a system, it is called forced oscillation.
    • Equation of motion: md2xdt2+bdxdt+kx=F0cos⁡(ωt)m\frac{d^2x}{dt^2} + b\frac{dx}{dt} + kx = F_0 \cos(\omega t)mdt2d2x​+bdtdx​+kx=F0​cos(ωt)
      • F0F_0F0​: Amplitude of the external force.
      • ω\omegaω: Angular frequency of the external force.
  2. Resonance:

    • When the frequency of the external force matches the natural frequency of the system, the amplitude of oscillation becomes maximum.
    • Example: Swing pushed at regular intervals matching its natural frequency.

Energy Dissipation in Damped Motion

  1. Energy Loss:
    • In damped motion, energy is dissipated over time due to resistive forces.
    • The total energy decreases exponentially: E=E0e−bt/mE = E_0 e^{-bt/m}E=E0​e−bt/m
      • E0E_0E0​: Initial energy.
      • bbb: Damping coefficient.
      • mmm: Mass.

Practical Applications of SHM

  1. Clocks:

    • Pendulum clocks use the periodic motion of a pendulum for timekeeping.
  2. Seismographs:

    • Used to measure ground motion during earthquakes, based on the oscillation of a mass.
  3. Tuning Forks:

    • Vibrations of a tuning fork produce sound waves with a specific frequency.
  4. Shock Absorbers:

    • Use damped oscillations to minimize vibrations in vehicles.

Numerical Examples

  1. Example 1: A spring with a constant k=200 N/mk = 200 \, N/mk=200N/m is attached to a 5 kg5 \, kg5kg mass. Find the time period of the oscillations.

    • Formula: T=2πmkT = 2\pi \sqrt{\frac{m}{k}}T=2πkm​​
    • Substituting values: T=2π5200=2π0.025=2π⋅0.158≈0.99 sT = 2\pi \sqrt{\frac{5}{200}} = 2\pi \sqrt{0.025} = 2\pi \cdot 0.158 \approx 0.99 \, sT=2π2005​​=2π0.025​=2π⋅0.158≈0.99s
  2. Example 2: A pendulum of length 1.5 m1.5 \, m1.5m is oscillating. Find its time period. (Take g=9.8 m/s2g = 9.8 \, m/s^2g=9.8m/s2).

    • Formula: T=2πLgT = 2\pi \sqrt{\frac{L}{g}}T=2πgL​​
    • Substituting values: T=2π1.59.8=2π⋅0.39≈2.45 sT = 2\pi \sqrt{\frac{1.5}{9.8}} = 2\pi \cdot 0.39 \approx 2.45 \, sT=2π9.81.5​​=2π⋅0.39≈2.45s

Wave Motion and SHM

  1. Relation Between SHM and Wave Motion:
    • SHM is the basis of wave motion, where particles oscillate about their equilibrium position in a periodic manner.
    • A sinusoidal wave can be represented as: y(x,t)=Asin⁡(kx−ωt+ϕ)y(x, t) = A \sin(kx - \omega t + \phi)y(x,t)=Asin(kx−ωt+ϕ)
      • AAA: Amplitude.
      • kkk: Wave number (k=2πλk = \frac{2\pi}{\lambda}k=λ2π​).
      • ω\omegaω: Angular frequency.
      • ϕ\phiϕ: Phase constant.
      • λ\lambdaλ: Wavelength.

Combined SHM

  1. Superposition of Two SHMs:

    • When two SHMs of the same frequency are combined: x(t)=A1cos⁡(ωt+ϕ1)+A2cos⁡(ωt+ϕ2)x(t) = A_1 \cos(\omega t + \phi_1) + A_2 \cos(\omega t + \phi_2)x(t)=A1​cos(ωt+ϕ1​)+A2​cos(ωt+ϕ2​)
    • The resultant amplitude is: A=A12+A22+2A1A2cos⁡(ϕ2−ϕ1)A = \sqrt{A_1^2 + A_2^2 + 2A_1A_2 \cos(\phi_2 - \phi_1)}A=A12​+A22​+2A1​A2​cos(ϕ2​−ϕ1​)​
  2. Lissajous Figures:

    • When two SHMs act perpendicular to each other, their superposition can create patterns known as Lissajous figures.

Practical Applications of Periodic Motion

  1. Mechanical Systems:

    • Springs and pendulums in timekeeping devices (e.g., clocks).
    • Vibration isolation in machinery using dampers.
  2. Acoustic Applications:

    • Tuning forks for generating sound waves.
    • Resonance in musical instruments.
  3. Electromagnetic Applications:

    • Oscillations in LC circuits for generating radio waves.
    • Resonance in antennas for signal reception.
  4. Medical Applications:

    • Ultrasonic imaging uses wave motion for diagnostic purposes.

Damped Oscillations in Real Life

  1. Car Suspension:

    • Shock absorbers in vehicles dampen oscillations for a smoother ride.
  2. Bridge Vibrations:

    • Damping is used to minimize oscillations caused by wind or traffic.
  3. Earthquake Engineering:

    • Seismic dampers in buildings reduce oscillations during earthquakes.

Resonance in Practical Situations

  1. Musical Instruments:

    • String instruments use resonance to amplify sound.
  2. Structural Engineering:

    • Resonance can cause structural failures (e.g., Tacoma Narrows Bridge collapse).
    • Structures are designed to avoid natural frequencies matching external vibrations.
  3. Microwave Ovens:

    • Utilize resonance to heat water molecules efficiently.

Numerical Examples

  1. Example 1: Two SHMs with amplitudes 3 cm3 \, cm3cm and 4 cm4 \, cm4cm are superposed at a phase difference of 90∘90^\circ90∘. Find the resultant amplitude.

    • Formula: A=A12+A22+2A1A2cos⁡(ϕ)A = \sqrt{A_1^2 + A_2^2 + 2A_1A_2 \cos(\phi)}A=A12​+A22​+2A1​A2​cos(ϕ)​
    • Substituting values: A=32+42+2⋅3⋅4⋅cos⁡90∘A = \sqrt{3^2 + 4^2 + 2 \cdot 3 \cdot 4 \cdot \cos 90^\circ}A=32+42+2⋅3⋅4⋅cos90∘​ A=9+16+0=25=5 cmA = \sqrt{9 + 16 + 0} = \sqrt{25} = 5 \, cmA=9+16+0​=25​=5cm
  2. Example 2: A pendulum with a length of 2.25 m2.25 \, m2.25m oscillates with a period of 3 s3 \, s3s. Find the acceleration due to gravity.

    • Formula: T=2πLg  ⟹  g=4π2LT2T = 2\pi \sqrt{\frac{L}{g}} \implies g = \frac{4\pi^2L}{T^2}T=2πgL​​⟹g=T24π2L​
    • Substituting values: g=4π2⋅2.2532=88.29≈9.8 m/s2g = \frac{4\pi^2 \cdot 2.25}{3^2} = \frac{88.2}{9} \approx 9.8 \, m/s^2g=324π2⋅2.25​=988.2​≈9.8m/s2

Recap: Key Points to Remember

  • Periodic motion repeats after regular intervals, with SHM being a key example.
  • Damped and forced oscillations are extensions of SHM, with real-life applications in vehicles, structures, and electronics.
  • Resonance occurs when the natural frequency of a system matches an external periodic force, leading to large oscillations.

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